To measure the field B between the poles of an electromagnet, a small test loop of area 1 cm2, resistance 10 Ω and 20 turns is pulled out of it. A galvanometer shows that a total , charge of 2μ C passed through the loop. The value of B is

Question

To measure the field B between the poles of an electromagnet, a small test loop of area 1 cm2, resistance 10 Ω and 20 turns is pulled out of it. A galvanometer shows that a total , charge of 2μ C passed through the loop. The value of B is (A) 0.001 T (B) 0.01 T (C) 0.1 T (D) 1.0 T

Tardigrade Admin · Accepted Answer

q = (e/R) dt = ((B1 - B2)NA/R) 2 μ c = ((B - 0) 20 × 10-4/10) = 0.01T

Q. To measure the field B between the poles of an electromagnet, a small test loop of area $1 c m^{2}$ , resistance $10 Ω$ and 20 turns is pulled out of it. A galvanometer shows that a total , charge of $2 μ C$ passed through the loop. The value of B is

0.001 T

0.01 T

0.1 T

1.0 T

$q = \frac{e}{R} d t = \frac{( B _{1} - B _{2} ) N A}{R}$
$2 μ c = \frac{( B - 0 ) 20 \times 1 0 ^{- 4}}{10} = 0.01 T$

Q. To measure the field B between the poles of an electromagnet, a small test loop of area 1cm2, resistance 10Ω and 20 turns is pulled out of it. A galvanometer shows that a total , charge of 2μC passed through the loop. The value of B is