To find the radius of a circular path of an electron, when subjected to a perpendicular magnetic field is:

Question

To find the radius of a circular path of an electron, when subjected to a perpendicular magnetic field is: (A)  (m upsilon /Be)  (B)  (me/B)  (C)  (mE/B)  (D)  (Be/m upsilon )

Tardigrade Admin · Accepted Answer

Centripetel force =(m upsilon 2/r) and force on a moving electron in the magnetic field =Be upsilon Hence, (m upsilon 2/r)=Be upsilon or r=(m upsilon /Be) (Here, r is the radius of circular path)

Q. To find the radius of a circular path of an electron, when subjected to a perpendicular magnetic field is:

$\frac{m υ}{B e}$

$\frac{m e}{B}$

$\frac{m E}{B}$

$\frac{B e}{m υ}$

Centripetel force $= \frac{m υ ^{2}}{r}$ and force on a moving electron in the magnetic field $= B e υ$ Hence, $\frac{m υ ^{2}}{r} = B e υ$ or $r = \frac{m υ}{B e}$ (Here, r is the radius of circular path)

Q. To find the radius of a circular path of an electron, when subjected to a perpendicular magnetic field is:

Bemυ​

Bme​

BmE​

mυBe​

Centripetel force =rmυ2​ and force on a moving electron in the magnetic field =Beυ Hence, rmυ2​=Beυ or r=Bemυ​ (Here, r is the radius of circular path)

$\frac{m υ}{B e}$

$\frac{m e}{B}$

$\frac{m E}{B}$

$\frac{B e}{m υ}$

Centripetel force $= \frac{m υ ^{2}}{r}$ and force on a moving electron in the magnetic field $= B e υ$ Hence, $\frac{m υ ^{2}}{r} = B e υ$ or $r = \frac{m υ}{B e}$ (Here, r is the radius of circular path)