To decrease the range of an ammeter, its resistance need to be increased. An ammeter has resistance R0 and range I. Which of the following resistance can be connected in series with it to decrease its range to (1/n) ?

Question

To decrease the range of an ammeter, its resistance need to be increased. An ammeter has resistance R0 and range I. Which of the following resistance can be connected in series with it to decrease its range to (1/n) ? (A)  (R0/n)  (B)  (R0/(n - 1))  (C)  (R0/(n + 1))  (D) None of these

Tardigrade Admin · Accepted Answer

A galvanometer can be converted into an ammeter by using a low resistance wire in parallel with the galvanometer. The range of ammeter can be increased but cannot be decreased. The reason is that a series resistor cannot change the current that will produce full deflection.
A shunt connected in parallel is given by

S = \frac{I _{g} G}{I - I _{g}}

If

I < I_{g}

, then the value of S is negative.
Hence, a galvanometer cannot be converted into an ammeter of range

I < I_{g}

Q. To decrease the range of an ammeter, its resistance need to be increased. An ammeter has resistance $R_{0}$ and range I. Which of the following resistance can be connected in series with it to decrease its range to $\frac{1}{n}$ ?

$\frac{R _{0}}{n}$

$\frac{R _{0}}{( n - 1 )}$

$\frac{R _{0}}{( n + 1 )}$

None of these

Q. To decrease the range of an ammeter, its resistance need to be increased. An ammeter has resistance R0​ and range I. Which of the following resistance can be connected in series with it to decrease its range to n1​ ?

nR0​​

(n−1)R0​​

(n+1)R0​​

None of these

Q. To decrease the range of an ammeter, its resistance need to be increased. An ammeter has resistance $R_{0}$ and range I. Which of the following resistance can be connected in series with it to decrease its range to $\frac{1}{n}$ ?

$\frac{R _{0}}{n}$

$\frac{R _{0}}{( n - 1 )}$

$\frac{R _{0}}{( n + 1 )}$