Time taken to heat water upto a temperature of 40° C (from room temperature) is t1 and time taken to heat mustard oil (of same mass and at room temperature) upto a temperature of 40° C is t2, then (given mustard oil has smaller heat capacity)

Question

Time taken to heat water upto a temperature of 40° C (from room temperature) is t1 and time taken to heat mustard oil (of same mass and at room temperature) upto a temperature of 40° C is t2, then (given mustard oil has smaller heat capacity) (A) t1=t2 (B) t1 >t2 (C) t2 >t1 (D) t1 and t2 both are less than 10 min

Tardigrade Admin · Accepted Answer

The heat capacity of a substance is S=(Δ Q/Δ T). The heat capacity of mustard oil is less than that of water for same mass. So, same temperature rise (Δ T=40° C ), the quantity of heat (Δ Q) would be less than that is required by the same amount of water. Hence, the time taken by water (t1) to heat upto 40° C will be higher than that of mustard oil (t2), i.e. t1>t2.

Q. Time taken to heat water upto a temperature of $4 0^{\circ} C$ (from room temperature) is $t_{1}$ and time taken to heat mustard oil (of same mass and at room temperature) upto a temperature of $4 0^{\circ} C$ is $t_{2}$ , then (given mustard oil has smaller heat capacity)

$t_{1} = t_{2}$

$t_{1} > t_{2}$

$t_{2} > t_{1}$

$t_{1}$ and $t_{2}$ both are less than $10 min$

Q. Time taken to heat water upto a temperature of 40∘C (from room temperature) is t1​ and time taken to heat mustard oil (of same mass and at room temperature) upto a temperature of 40∘C is t2​, then (given mustard oil has smaller heat capacity)

t1​=t2​

t1​>t2​

t2​>t1​

t1​ and t2​ both are less than 10min

Q. Time taken to heat water upto a temperature of $4 0^{\circ} C$ (from room temperature) is $t_{1}$ and time taken to heat mustard oil (of same mass and at room temperature) upto a temperature of $4 0^{\circ} C$ is $t_{2}$ , then (given mustard oil has smaller heat capacity)

$t_{1} = t_{2}$

$t_{1} > t_{2}$

$t_{2} > t_{1}$

$t_{1}$ and $t_{2}$ both are less than $10 min$