Question

Three resistance of 10$\Omega$ , 5$\Omega$ , 2$\Omega$ respectively are connected in parallel. New resistance will be

• A. more than 10$\Omega$
• B. between 10$\Omega$ and 5 $\Omega$
• C. between 5$\Omega$ and 2$\Omega$
• D. less than 2$\Omega$ .

Answer 1

Answer: (D)

$\frac{1}{R_p}=\frac{1}{R_1}+\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}=\frac{1}{10}+\frac{1}{5}+\frac{1}{2}=\frac{8}{10}$
Hence $R_p=1.25\Omega$