Three point charges +q,+2 q and -4 q where q=0.1 μ C, are placed at the vertices of an equilateral triangle of side 10 cm as shown in. The potential energy of the system is

Question

Three point charges +q,+2 q and -4 q where q=0.1 μ C, are placed at the vertices of an equilateral triangle of side 10 cm as shown in. The potential energy of the system is (A) 3 × 10-3 J (B) -3 × 10-3 J (C) 9 × 10-3 J (D) -9 × 10-3 J

Tardigrade Admin · Accepted Answer

U (1/4 0) (2q2/a) (8q2/a) (4q2/a) U (1/4 0) (10q2/a) U (9 109 (0.1 10 6)2/(10)100|) U = - 9 Ã 10-3J

Q. Three point charges $+ q, + 2 q$ and $- 4 q$ where $q = 0.1 μ C$ , are placed at the vertices of an equilateral triangle of side $10 c m$ as shown in. The potential energy of the system is

$3 \times 1 0^{- 3} J$

$- 3 \times 1 0^{- 3} J$

$9 \times 1 0^{- 3} J$

$- 9 \times 1 0^{- 3} J$

$U \frac{1}{4 _{0}} \frac{2 q ^{2}}{a} \frac{8 q ^{2}}{a} \frac{4 q ^{2}}{a}$
$U \frac{1}{4 _{0}} \frac{10 q ^{2}}{a}$
$U \frac{9 1 0 ^{9} ( 0.1 1 0 ^{6} ) ^{2}}{\frac{10}{100} ∣}$
U = - 9 × 10^-3J

Q. Three point charges +q,+2q and −4q where q=0.1μC, are placed at the vertices of an equilateral triangle of side 10cm as shown in. The potential energy of the system is

3×10−3J

−3×10−3J

9×10−3J

−9×10−3J