Three particles of masses 1 kg , 2 kg and 3 kg are placed at three corners of a right angled triangle of sides 3 cm , 4 cm and 5 cm as shown in the figure. The centre of mass from 1 kg mass is

Question

Three particles of masses 1 kg , 2 kg and 3 kg are placed at three corners of a right angled triangle of sides 3 cm , 4 cm and 5 cm as shown in the figure. The centre of mass from 1 kg mass is (A) (1.33 cm, 1.5 cm) (B) (2 cm, 1 cm) (C) (1.14 cm, 1.5 cm) (D) (1.7 cm, 0.9 cm)

Tardigrade Admin · Accepted Answer

x=((1 × 0)+(2 × 4)+(3 × 0)/1+2+3) =(8/6)=1.33 cm y=((1) ×(0)+2(0)+3 × 3/1+2+3) =(9/6)=1.5 cm (x, y):(1.33,1.50 cm )

Q. Three particles of masses $1 k g, 2 k g$ and $3 k g$ are placed at three corners of a right angled triangle of sides $3 c m, 4 c m$ and $5 c m$ as shown in the figure. The centre of mass from $1 k g$ mass is

(1.33 cm, 1.5 cm)

(2 cm, 1 cm)

(1.14 cm, 1.5 cm)

(1.7 cm, 0.9 cm)

$x = \frac{( 1 \times 0 ) + ( 2 \times 4 ) + ( 3 \times 0 )}{1 + 2 + 3}$
$= \frac{8}{6} = 1.33 c m$
$y = \frac{( 1 ) \times ( 0 ) + 2 ( 0 ) + 3 \times 3}{1 + 2 + 3}$
$= \frac{9}{6} = 1.5 c m$
$(x, y) : (1.33, 1.50 c m)$

Q. Three particles of masses 1kg,2kg and 3kg are placed at three corners of a right angled triangle of sides 3cm,4cm and 5cm as shown in the figure. The centre of mass from 1kg mass is