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Q. Three particles of masses $1 \,kg , 2\, kg$ and $3 \,kg$ are placed at three corners of a right angled triangle of sides $3\, cm , 4 \,cm$ and $5 \,cm$ as shown in the figure. The centre of mass from $1 \,kg$ mass isPhysics Question Image

Solution:

$x=\frac{(1 \times 0)+(2 \times 4)+(3 \times 0)}{1+2+3} $
$=\frac{8}{6}=1.33 \,cm$
$y=\frac{(1) \times(0)+2(0)+3 \times 3}{1+2+3}$
$=\frac{9}{6}=1.5 \,cm$
$(x, y):(1.33,1.50 \,cm )$