Three identical particles are joined together by a thread as shown in figure. All the three particles are moving in a horizontal plane. If the velocity of the outermost particle is v0, then the ratio of tensions in the three sections of the string is

Question

Three identical particles are joined together by a thread as shown in figure. All the three particles are moving in a horizontal plane. If the velocity of the outermost particle is v0, then the ratio of tensions in the three sections of the string is <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/ea511f762700a09c47ec3307bc599b0a-.png" /> (A) 3: 5: 7 (B) 3: 4: 5 (C) 7 :11 :6 (D) 3: 5: 6

Tardigrade Admin · Accepted Answer

Let ω is the angular speed of revolution <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/3ba41f9d9bb6518d966bbd47324377b2-.png" /> T3=mω33l T2-T3=m ω22l ⇒ T2=mω25l T1-T2=mω22l ⇒ T1=m ω26l T3: T2: T1=3:5:6

Q. Three identical particles are joined together by a thread as shown in figure. All the three particles are moving in a horizontal plane. If the velocity of the outermost particle is $v_{0}$ , then the ratio of tensions in the three sections of the string is

$3 : 5 : 7$

$3 : 4 : 5$

$7 : 11 : 6$

$3 : 5 : 6$

Let $ω$ is the angular speed of revolution

$T_{3} = m ω^{3} 3 l$

$T_{2} - T_{3} = m ω^{2} 2 l$

$\Rightarrow T_{2} = m ω^{2} 5 l$

$T_{1} - T_{2} = m ω^{2} 2 l$

$\Rightarrow T_{1} = m ω^{2} 6 l$

$T_{3} : T_{2} : T_{1} = 3 : 5 : 6$

Q. Three identical particles are joined together by a thread as shown in figure. All the three particles are moving in a horizontal plane. If the velocity of the outermost particle is v0​, then the ratio of tensions in the three sections of the string is

3:5:7

3:4:5

7:11:6

3:5:6