Three ideal p-n junction diodes D1, D2 and D3 are connected as shown in the circuit. The potentials VA and VB can be changed. If VA=-5 V and VB=-10 V, then the resistance between A and B will be

Question

Three ideal p-n junction diodes D1, D2 and D3 are connected as shown in the circuit. The potentials VA and VB can be changed. <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/f284415163963584c8998abad13973bc-.png" /> If VA=-5 V and VB=-10 V, then the resistance between A and B will be (A) R (B) R / 2 (C) 3 R (D) 3 R / 2

Tardigrade Admin · Accepted Answer

When VA=-5 V and VB=-10 V D2 is reverse biased and D1 and D3 get forward biased, then RA B=(R/4)+(R/2)+(R/4)=R

Q. Three ideal $p - n$ junction diodes $D_{1}, D_{2}$ and $D_{3}$ are connected as shown in the circuit. The potentials $V_{A}$ and $V_{B}$ can be changed.

If $V_{A} = - 5 V$ and $V_{B} = - 10 V$ , then the resistance between $A$ and $B$ will be

$R$

$R /2$

$3 R$

$3 R /2$

When $V_{A} = - 5 V$ and $V_{B} = - 10 V$
$D_{2}$ is reverse biased and $D_{1}$ and $D_{3}$ get forward biased, then $R_{A B} = \frac{R}{4} + \frac{R}{2} + \frac{R}{4} = R$

Q. Three ideal p−n junction diodes D1​,D2​ and D3​ are connected as shown in the circuit. The potentials VA​ and VB​ can be changed. If VA​=−5V and VB​=−10V, then the resistance between A and B will be

R

R/2

3R

3R/2

When VA​=−5V and VB​=−10V D2​ is reverse biased and D1​ and D3​ get forward biased, then RAB​=4R​+2R​+4R​=R

Q. Three ideal $p - n$ junction diodes $D_{1}, D_{2}$ and $D_{3}$ are connected as shown in the circuit. The potentials $V_{A}$ and $V_{B}$ can be changed.

If $V_{A} = - 5 V$ and $V_{B} = - 10 V$ , then the resistance between $A$ and $B$ will be

$R$

$R /2$

$3 R$

$3 R /2$

When $V_{A} = - 5 V$ and $V_{B} = - 10 V$
$D_{2}$ is reverse biased and $D_{1}$ and $D_{3}$ get forward biased, then $R_{A B} = \frac{R}{4} + \frac{R}{2} + \frac{R}{4} = R$