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Q. Three ideal $p-n$ junction diodes $D_{1}, D_{2}$ and $D_{3}$ are connected as shown in the circuit. The potentials $V_{A}$ and $V_{B}$ can be changed.
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If $V_{A}=-5\, V$ and $V_{B}=-10\, V$, then the resistance between $A$ and $B$ will be

Semiconductor Electronics: Materials Devices and Simple Circuits

Solution:

When $V_{A}=-5\, V$ and $V_{B}=-10\, V$
$D_{2}$ is reverse biased and $D_{1}$ and $D_{3}$ get forward biased, then $R_{A B}=\frac{R}{4}+\frac{R}{2}+\frac{R}{4}=R$