Three forces starts acting simultaneously on a particle moving with velocity v . These forces are represented in magnitude and direction by the three sides of a triangle ABC. The particle will now move with velocity

Question

Three forces starts acting simultaneously on a particle moving with velocity v . These forces are represented in magnitude and direction by the three sides of a triangle ABC. The particle will now move with velocity <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/d700eaa3b29b64e750f7d34a44acd5c9-.png" /> (A)  vecv remaining unchanged (B) less than vecv (C) Greater than vecv (D)  vecv in the direction of the largest force BC

Tardigrade Admin · Accepted Answer

Velocity remains constant because no external force is acting on the system.

Q. Three forces starts acting simultaneously on a particle moving with velocity $v$ . These forces are represented in magnitude and direction by the three sides of a triangle ABC. The particle will now move with velocity

$v$ remaining unchanged

less than $v$

Greater than $v$

$v$ in the direction of the largest force BC

Velocity remains constant because no external force is acting on the system.

Q. Three forces starts acting simultaneously on a particle moving with velocity v . These forces are represented in magnitude and direction by the three sides of a triangle ABC. The particle will now move with velocity

v remaining unchanged

less than v

Greater than v

v in the direction of the largest force BC

Velocity remains constant because no external force is acting on the system.

Q. Three forces starts acting simultaneously on a particle moving with velocity $v$ . These forces are represented in magnitude and direction by the three sides of a triangle ABC. The particle will now move with velocity

$v$ remaining unchanged

less than $v$

Greater than $v$

$v$ in the direction of the largest force BC