Q.
Three Faradays of electricity are passed through molten Al2O3, aqueous solution of CuSO4 and molten NaCl taken in three different electrolytic cells. Then the mole ratio of Al,Cu and Na deposited on the cathode will be
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J & K CETJ & K CET 2011Electrochemistry
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Solution:
∵Al3++3e−→Al ∴3F of electricity will deposite 1 mole of AI. ∵Cu2++2e−→Cu ∴3F of electricity will deposite 1.5 mole of Cu. ∵Na++e−→Na ∴3F of electricity will deposite 3 mole of Na.
Hence, the mole ratio of Al,Cu and Na deposited on the cathode will be 1:1.5:3 or 2:3:6.