Three concurrent forces of the same magnitude are in equilibrium. What is the angle between the forces? Also, name the triangle formed by the forces as sides

Question

Three concurrent forces of the same magnitude are in equilibrium. What is the angle between the forces? Also, name the triangle formed by the forces as sides (A) 60° equilateral triangle (B) 120° equilateral triangle (C) 120', 30°, 30° an isosceles triangle (D) 120° an obtuse triangle

Tardigrade Admin · Accepted Answer

In N forces of equal magnitude works on a single point and their resultant is zero, then angle between any two forces is θ=(360°/N)=(360°/3)=120° If these 3 vectors are represented by three sides of triangle, then they form equilateral triangle.

Q. Three concurrent forces of the same magnitude are in equilibrium. What is the angle between the forces? Also, name the triangle formed by the forces as sides

$6 0^{\circ}$ equilateral triangle

$12 0^{\circ}$ equilateral triangle

$12 0^{'}, 3 0^{\circ}, 3 0^{\circ}$ an isosceles triangle

$12 0^{\circ}$ an obtuse triangle

In $N$ forces of equal magnitude works on a single point and their resultant is zero,
then angle between any two forces is
$θ = \frac{36 0 ^{\circ}}{N} = \frac{36 0 ^{\circ}}{3} = 12 0^{\circ}$
If these $3$ vectors are represented by three sides of triangle,
then they form equilateral triangle.

Q. Three concurrent forces of the same magnitude are in equilibrium. What is the angle between the forces? Also, name the triangle formed by the forces as sides

60∘ equilateral triangle

120∘ equilateral triangle

120′,30∘,30∘ an isosceles triangle

120∘ an obtuse triangle

In N forces of equal magnitude works on a single point and their resultant is zero, then angle between any two forces is θ=N360∘​=3360∘​=120∘ If these 3 vectors are represented by three sides of triangle, then they form equilateral triangle.

$6 0^{\circ}$ equilateral triangle

$12 0^{\circ}$ equilateral triangle

$12 0^{'}, 3 0^{\circ}, 3 0^{\circ}$ an isosceles triangle

$12 0^{\circ}$ an obtuse triangle

In $N$ forces of equal magnitude works on a single point and their resultant is zero,
then angle between any two forces is
$θ = \frac{36 0 ^{\circ}}{N} = \frac{36 0 ^{\circ}}{3} = 12 0^{\circ}$
If these $3$ vectors are represented by three sides of triangle,
then they form equilateral triangle.