Three charges are placed at the vertices of equilateral triangle of charge q each. What is the net potential energy, if the side of equilateral Δ is l ?

Question

Three charges are placed at the vertices of equilateral triangle of charge q each. What is the net potential energy, if the side of equilateral Δ is l ? (A) (1/4 π ε0) (q2/l) (B) (1/4 π ε0) (2 q2/l) (C) (1/4 π ε0) (3 q2/l) (D) (1/4 π ε0) (4 q2/l)

Tardigrade Admin · Accepted Answer

U=(1/4 π ε0) ⋅ (Q1 Q2/r) ; net potential energy is U net =3 × (1/4 π ε0) ⋅ (q2/l)

Q. Three charges are placed at the vertices of equilateral triangle of charge $q$ each. What is the net potential energy, if the side of equilateral $Δ$ is $l ?$

$\frac{1}{4 π ε _{0}} \frac{q ^{2}}{l}$

$\frac{1}{4 π ε _{0}} \frac{2 q ^{2}}{l}$

$\frac{1}{4 π ε _{0}} \frac{3 q ^{2}}{l}$

$\frac{1}{4 π ε _{0}} \frac{4 q ^{2}}{l}$

$U = \frac{1}{4 π ε _{0}} \cdot \frac{Q _{1} Q _{2}}{r};$ net potential energy is
$U_{n e t} = 3 \times \frac{1}{4 π ε _{0}} \cdot \frac{q ^{2}}{l}$

Q. Three charges are placed at the vertices of equilateral triangle of charge q each. What is the net potential energy, if the side of equilateral Δ is l?

4πε0​1​lq2​

4πε0​1​l2q2​

4πε0​1​l3q2​

4πε0​1​l4q2​