Question

Three cards drawn successively, without replacement from a pack of $52$ well shuffled cards, then the probability that first two cards are kings and the third card drawn is an ace, is

• A. $\frac{2}{5525}$
• B. $\frac{1}{5525}$
• C. $\frac{2}{5527}$
• D. $\frac{1}{5527}$

Answer 1

Answer: (A)

Let $K$ denote the event that the card drawn is king and $A$ be the event that the card drawn is an ace. Clearly, we have to find $P(KKA)$.
Now, $P(K)=\frac{4}{52}$
Also, $P(K|K)$ is the probability of second king with the condition that one king has already been drawn.
$\therefore P(K|K)=\frac{3}{51}$
Lastly, $P(A|KK)$ is the probability of third drawn card to be an ace, with the condition that two kings have already been drawn.
$\therefore P(A|KK)=\frac{4}{50}$
By multiplication law of probability, we have
$P(KKA)=P(K).P(K|K).P(A|KK)$
$=\frac{4}{52}\times \frac{3}{51}\times \frac{4}{50}$
$=\frac{2}{5525}$