Three capacitors of capacitance 3 μ F are connected in a circuit. Then their maximum and minimum capacitances will be

Question

Three capacitors of capacitance 3 μ F are connected in a circuit. Then their maximum and minimum capacitances will be (A) 9 μ F , 1 μ F (B) 8 μ F , 2 μ F (C) 9 μ F , 0 μ F (D) 3 μ F , 2 μ F

Tardigrade Admin · Accepted Answer

C max =n C=3 × 3=9 μ F , C min =(C/n)=(3/3)=1 μ F

Q. Three capacitors of capacitance $3 μ F$ are connected in a circuit. Then their maximum and minimum capacitances will be

$9 μ F, 1 μ F$

$8 μ F, 2 μ F$

$9 μ F, 0 μ F$

$3 μ F, 2 μ F$

$C_{m a x} = n C = 3 \times 3 = 9 μ F$ ,
$C_{m i n} = \frac{C}{n} = \frac{3}{3} = 1 μ F$

Q. Three capacitors of capacitance 3μF are connected in a circuit. Then their maximum and minimum capacitances will be

9μF,1μF

8μF,2μF

9μF,0μF

3μF,2μF