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  4. Three capacitors of capacitance 3 μ F are connected in a circuit. Then their maximum and minimum capacitances will be

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Q. Three capacitors of capacitance $3\, \mu F$ are connected in a circuit. Then their maximum and minimum capacitances will be

Electrostatic Potential and Capacitance

Solution:

$C_{\max }=n C=3 \times 3=9\, \mu F $,
$ C_{\min }=\frac{C}{n}=\frac{3}{3}=1\, \mu F$