Three capacitors each of capacitance C and of breakdown voltage V are joined in series. The capacitance and breakdown voltage of the combination will be

Question

Three capacitors each of capacitance C and of breakdown voltage V are joined in series. The capacitance and breakdown voltage of the combination will be (A) 3C, (V/3) (B)  (C/ 3), 3V (C) 3C, 3V (D)  (C/ 3) , (V/ 3)

Tardigrade Admin · Accepted Answer

In series, C text eq =(C/3), V text eq =3 V

Q. Three capacitors each of capacitance $C$ and of breakdown voltage $V$ are joined in series. The capacitance and breakdown voltage of the combination will be

3C, $\frac{V}{3}$

$\frac{C}{3},$ 3V

3C, 3V

$\frac{C}{3}, \frac{V}{3}$

In series, $C_{eq} = \frac{C}{3},$
$V_{eq} = 3 V$

Q. Three capacitors each of capacitance C and of breakdown voltage V are joined in series. The capacitance and breakdown voltage of the combination will be

3C, 3V​

3C​, 3V