Question

Three capacitors 3 $\mu$ F, 10 $\mu$ F, and 15 $\mu$ f are connected in series to a voltage source of 100 V. The charge on 15 $\mu$ F is:

• A. 22 $\mu$ C
• B. 100 $\mu$ C
• C. 2800 $\mu$ C
• D. 200 $\mu$ C

Answer 1

Answer: (D)

As the capacitors are connected in series. Hence, their equivalent capacitance is given by $\frac{1}{C_{eq}}=\frac{1}{C_1}+\frac{1}{C_2}+\frac{1}{C_3}=\frac{1}{3}+\frac{1}{10}+\frac{1}{15}$ $=\frac{10+3+2}{30}$ $\frac{1}{C_{eq}}=\frac{15}{30}=\frac{1}{2}\Rightarrow C_{eq}=2\mu F$ As the charge on each capacitor will be same $=C_{eq}V=2\times 100=20\mu C$