Question

Three capacitors 3 $ \mu $ F, 10 $ \mu $ F, and 15 $ \mu $ f are connected in series to a voltage source of 100 V. The charge on 15 $ \mu $ F is:

• A. 22 $ \mu $ C
• B. 100 $ \mu $ C
• C. 2800 $ \mu $ C
• D. 200 $ \mu $ C

Answer 1

Answer: (D)

As the capacitors are connected in series. Hence, their equivalent capacitance is given by $ \frac{1}{{{C}_{eq}}}=\frac{1}{{{C}_{1}}}+\frac{1}{{{C}_{2}}}+\frac{1}{{{C}_{3}}}=\frac{1}{3}+\frac{1}{10}+\frac{1}{15} $ $ =\frac{10+3+2}{30} $ $ \frac{1}{{{C}_{eq}}}=\frac{15}{30}=\frac{1}{2}\Rightarrow {{C}_{eq}}=2\mu F $ As the charge on each capacitor will be same $ ={{C}_{eq}}V=2\times 100=20\mu C $