Three blocks of masses m1,m2 and m3 are placed on a horizontal frictionless surface. A force of 40 N pulls the system then calculate the value of T , if m1=10 kg, m2=6 kg, ⁡m3=4 kg .

Question

Three blocks of masses m1,m2 and m3 are placed on a horizontal frictionless surface. A force of 40 N pulls the system then calculate the value of T , if m1=10 kg, m2=6 kg, ⁡m3=4 kg . <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-geru2dlhe9ni.png" /> (A) 40 N (B) 20 N (C) 10 N (D) 5 N

Tardigrade Admin · Accepted Answer

a=(F/m1 + m2 + m3) a=(40/10 + 6 + 4) a=2 m s- 2 taking blocks of masses m2 and m3 as a system, 40-T=10× 2 T=20 N

Q. Three blocks of masses $m_{1}, m_{2}$ and $m_{3}$ are placed on a horizontal frictionless surface. A force of $40 N$ pulls the system then calculate the value of $T$ , if $m_{1} = 10 k g, m_{2} = 6 k g, m_{3} = 4 k g$ .

$40 N$

$20 N$

$10 N$

$5 N$

$a = \frac{F}{m _{1} + m _{2} + m _{3}}$
$a = \frac{40}{10 + 6 + 4}$
$a = 2 m s^{- 2}$
taking blocks of masses $m_{2}$ and $m_{3}$ as a system,
$40 - T = 10 \times 2$
$T = 20 N$

Q. Three blocks of masses m1​,m2​ and m3​ are placed on a horizontal frictionless surface. A force of 40N pulls the system then calculate the value of T , if m1​=10kg,m2​=6kg,⁡m3​=4kg .

40N

20N

10N

5N