Three blocks of masses m1,m2 and m3 are connected by massless string as shown kept on a frictionless table. They are pulled with a force T3=40N. If m1=10 kg,m2=6 kg and m3=4 text kg, the tension T2 will be:

Question

Three blocks of masses m1,m2 and m3 are connected by massless string as shown kept on a frictionless table. They are pulled with a force T3=40N. If m1=10 kg,m2=6 kg and m3=4 text kg, the tension T2 will be: (A) 20 N (B) 40 N (C) 10 N (D) 32 N

Tardigrade Admin · Accepted Answer

Common acceleration a=(F/m1+m2+m3) a=(40/10+6+4)=2 m/s2 Equation of motion of m3 is T3-T2=m3a 40-T2=4× 2 ⇒ T2=32N

Q. Three blocks of masses $m_{1}, m_{2}$ and $m_{3}$ are connected by massless string as shown kept on a frictionless table.
They are pulled with a force $T_{3} = 40 N .$ If $m_{1} = 10 k g, m_{2} = 6 k g$ and $m_{3} = 4 k g,$ the tension $T_{2}$ will be:

20 N

40 N

10 N

32 N

16 N

Common acceleration
$a = \frac{F}{m _{1} + m _{2} + m _{3}}$
$a = \frac{40}{10 + 6 + 4} = 2 m / s^{2}$
Equation of motion of $m_{3}$ is $T_{3} - T_{2} = m_{3} a$
$40 - T_{2} = 4 \times 2$
$\Rightarrow$ $T_{2} = 32 N$

Q. Three blocks of masses m1​,m2​ and m3​ are connected by massless string as shown kept on a frictionless table.They are pulled with a force T3​=40N. If m1​=10kg,m2​=6kg and m3​=4kg, the tension T2​ will be: