Three blocks of masses 2 kg , 3 kg and 5 kg are connected to each other with light string and are then placed on a frictionless surface as shown in the figure. The system is pulled by a force F=10 N, then tension T1=

Question

Three blocks of masses 2 kg , 3 kg and 5 kg are connected to each other with light string and are then placed on a frictionless surface as shown in the figure. The system is pulled by a force F=10 N, then tension T1= (A) 1 N (B) 5 N (C) 8 N (D) 10 N

Tardigrade Admin · Accepted Answer

Total mass of the system, M=m1+m2+m3 =2+3+5 =10 kg Force F=10 N Hence, acceleration, a=(F/M)=1 ms -2 Now, tension T1 can be calculated as, T1=(m2+m3) a=8 × 1=8 N

Q. Three blocks of masses $2 k g, 3 k g$ and $5 k g$ are connected to each other with light string and are then placed on a frictionless surface as shown in the figure. The system is pulled by a force $F = 10 N$ , then tension $T_{1} =$

1 N

5 N

8 N

10 N

Total mass of the system, $M = m_{1} + m_{2} + m_{3}$ $< b r / >< b r / >= 2 + 3 + 5$
$= 10 k g$
Force $F = 10 N$
Hence, acceleration, $a = \frac{F}{M} = 1 m s^{- 2}$
Now, tension $T_{1}$ can be calculated as,
$T_{1} = (m_{2} + m_{3}) a = 8 \times 1 = 8 N$

Q. Three blocks of masses 2kg,3kg and 5kg are connected to each other with light string and are then placed on a frictionless surface as shown in the figure. The system is pulled by a force F=10N, then tension T1​=

1 N

5 N

8 N

10 N

Total mass of the system, M=m1​+m2​+m3​<br/><br/>=2+3+5 =10kg Force F=10N Hence, acceleration, a=MF​=1ms−2 Now, tension T1​ can be calculated as, T1​=(m2​+m3​)a=8×1=8N

Q. Three blocks of masses $2 k g, 3 k g$ and $5 k g$ are connected to each other with light string and are then placed on a frictionless surface as shown in the figure. The system is pulled by a force $F = 10 N$ , then tension $T_{1} =$

Total mass of the system, $M = m_{1} + m_{2} + m_{3}$ $< b r / >< b r / >= 2 + 3 + 5$
$= 10 k g$
Force $F = 10 N$
Hence, acceleration, $a = \frac{F}{M} = 1 m s^{- 2}$
Now, tension $T_{1}$ can be calculated as,
$T_{1} = (m_{2} + m_{3}) a = 8 \times 1 = 8 N$