Thermal capacity of 40 g of aluminum (s=0.2 cal / g K ) is

Question

Thermal capacity of 40 g of aluminum (s=0.2 cal / g K ) is (A) 168 J / ° C (B) 672 J / ° C (C) 840 J / ° C (D) 33.6 J / ° C

Tardigrade Admin · Accepted Answer

Thermal capacity = ms = 40 × 0.2 = 8 cal/ °C = 4.2 × 8 = 33.6 J/°C

Q. Thermal capacity of $40 g$ of aluminum $(s = 0.2 c a l / g K)$ is