There is formation of H2O2 in the upper atmosphere H2O + O→ 2OH → H2O2 Δ H = 72 kJ mol-1 Ea = 77 kJ mol-1 Ea for the bimolecular recombination of two OH radicals

Question

There is formation of H2O2 in the upper atmosphere H2O + O→ 2OH → H2O2 Δ H = 72 kJ mol-1 Ea = 77 kJ mol-1 Ea for the bimolecular recombination of two OH radicals (A) 149 kJ mol-1 (B) - 149 kJ mol-1 (C) 5 kJ mol-1 (D) - 5 kJ mol-1

Tardigrade Admin · Accepted Answer

Correct answer is (c) 5 kJ mol-1

Q. There is formation of $H_{2} O_{2}$ in the upper atmosphere
$H_{2} O + O \to 2 O H \to H_{2} O_{2}$
$Δ H = 72 k J m o l^{- 1} E_{a} = 77 k J m o l^{- 1}$
$E_{a}$ for the bimolecular recombination of two $O H$ radicals

$149 k J m o l^{- 1}$

$- 149 k J m o l^{- 1}$

$5 k J m o l^{- 1}$

$- 5 k J m o l^{- 1}$

Correct answer is (c) $5 k J m o l^{- 1}$

Q. There is formation of H2​O2​ in the upper atmosphere H2​O+O→2OH→H2​O2​ ΔH=72kJmol−1Ea​=77kJmol−1 Ea​ for the bimolecular recombination of two OH radicals

149kJmol−1

−149kJmol−1

5kJmol−1

−5kJmol−1