There is an electric field E in x -direction. If the work done in moving a charge of 0.2 C through a distance of 2 m along a line making an angle of 60° with x -axis is 4 J , the value of E is:

Question

There is an electric field E in x -direction. If the work done in moving a charge of 0.2 C through a distance of 2 m along a line making an angle of 60° with x -axis is 4 J , the value of E is: (A) 2 √3 N / C (B) 5 N / C (C) 4 N / C (D) 20 N / C

Tardigrade Admin · Accepted Answer

W= Fs cos θ F = qE E=(F/q)=(W/q s cos θ) =(4/0.2 × 2 cos 60°) =20 N / C

Q. There is an electric field $E$ in $x$ -direction. If the work done in moving a charge of 0.2 C through a distance of $2 m$ along a line making an angle of $6 0^{\circ}$ with $x$ -axis is $4 J,$ the value of $E$ is:

$23 N / C$

$5 N / C$

$4 N / C$

$20 N / C$

$W =$ Fs $cos θ$
$F = qE$
$E = \frac{F}{q} = \frac{W}{q s c o s θ}$
$= \frac{4}{0.2 \times 2 c o s 6 0 ^{\circ}}$
$= 20 N / C$

Q. There is an electric field E in x -direction. If the work done in moving a charge of 0.2 C through a distance of 2m along a line making an angle of 60∘ with x -axis is 4J, the value of E is:

23​N/C

5N/C

4N/C

20N/C