There is an air filled 1 pf parallel plate capacitor. When the plate separation is doubled and the space is filled with wax, the capacitance increases to 2 pf. The dielectric constant of wax is

Question

There is an air filled 1 pf parallel plate capacitor. When the plate separation is doubled and the space is filled with wax, the capacitance increases to 2 pf. The dielectric constant of wax is (A) 2 (B) 4 (C) 6 (D) 8

Tardigrade Admin · Accepted Answer

C = (ε0 A/d) = 1 pf and C' = (k ε0 A/2d) = 2 pf This gives k = 4.

Q. There is an air filled $1 p f$ parallel plate capacitor. When the plate separation is doubled and the space is filled with wax, the capacitance increases to $2 p f$ . The dielectric constant of wax is

2

4

6

8

$C = \frac{ε _{0} A}{d} = 1$ pf and $C^{'} = \frac{k ε _{0} A}{2 d} = 2 p f$
This gives k = 4.

Q. There is an air filled 1pf parallel plate capacitor. When the plate separation is doubled and the space is filled with wax, the capacitance increases to 2pf. The dielectric constant of wax is

2

4

6

8

C=dε0​A​=1 pf and C′=2dkε0​A​=2pf This gives k = 4.

Q. There is an air filled $1 p f$ parallel plate capacitor. When the plate separation is doubled and the space is filled with wax, the capacitance increases to $2 p f$ . The dielectric constant of wax is

$C = \frac{ε _{0} A}{d} = 1$ pf and $C^{'} = \frac{k ε _{0} A}{2 d} = 2 p f$
This gives k = 4.