There is a trolley in which there is a fixed inclined surface on which a smooth block of mass 5 kg is placed. Two horizontal forces of magnitude F1 and F2 are applied on the trolley as shown to keep the trolley at rest. The value of F1 - F2 is: (Assume there is no friction between the trolley and horizontal ground and g = 10 m s- 2 )

Question

There is a trolley in which there is a fixed inclined surface on which a smooth block of mass 5 kg is placed. Two horizontal forces of magnitude F1 and F2 are applied on the trolley as shown to keep the trolley at rest. The value of F1 - F2 is: (Assume there is no friction between the trolley and horizontal ground and g = 10 m s- 2 ) <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-vxzfy1slz3qm.png" /> (A) 0N (B) 24N (C) -24 N (D) -30N

Tardigrade Admin · Accepted Answer

There is a trolley for which F1+Nsin37° =F2 <img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/p-vxzfy1slj4qf.png" /> F1-F2=[- N sin 37 ° ] . . . (1) N=[m g cos 37 ° ] . . . (2) F1-F2=-mgcos37° sin37° =-5× 10× (4/5)× (3/5)=-24 N

$0 N$

$24 N$

$- 24 N$

$- 30 N$

There is a trolley for which
$F_{1} + N s in 3 7^{\circ} = F_{2}$

$F_{1} - F_{2} = [- N s in 3 7^{\circ}]$ . . . (1)
$N = [m g cos 3 7^{\circ}]$ . . . (2)
$F_{1} - F_{2} = - m g cos 3 7^{\circ} s in 3 7^{\circ}$
$= - 5 \times 10 \times \frac{4}{5} \times \frac{3}{5} = - 24 N$

0N

24N

−24N

−30N

There is a trolley for which F1​+Nsin37∘=F2​ F1​−F2​=[−Nsin37∘] . . . (1) N=[mgcos37∘] . . . (2) F1​−F2​=−mgcos37∘sin37∘ =−5×10×54​×53​=−24N

$0 N$

$24 N$

$- 24 N$

$- 30 N$

There is a trolley for which
$F_{1} + N s in 3 7^{\circ} = F_{2}$

$F_{1} - F_{2} = [- N s in 3 7^{\circ}]$ . . . (1)
$N = [m g cos 3 7^{\circ}]$ . . . (2)
$F_{1} - F_{2} = - m g cos 3 7^{\circ} s in 3 7^{\circ}$
$= - 5 \times 10 \times \frac{4}{5} \times \frac{3}{5} = - 24 N$