There is a mixture of n moles of helium gas and 2n moles of oxygen gas. The value of (CP/CV) for the mixture is

Question

There is a mixture of n moles of helium gas and 2n moles of oxygen gas. The value of (CP/CV) for the mixture is (A) (23/15) (B) (40/27) (C) (67/45) (D) (19/13)

Tardigrade Admin · Accepted Answer

(&gamma; )mix=(n1 cp1 + n2 cp2/n1 cv1 + n2 cv2)=(n ((5/2) R) + 2 n ((7/2) R)/n ((3)2 R) + 2 n ((5)2 R)=(5 + 14/3 + 10)=(19/13)

Q. There is a mixture of $n$ moles of helium gas and $2 n$ moles of oxygen gas. The value of $\frac{C _{P}}{C _{V}}$ for the mixture is

$\frac{23}{15}$

$\frac{40}{27}$

$\frac{67}{45}$

$\frac{19}{13}$

$(γ)_{mi x} = \frac{n _{1} c _{p_{1}} + n _{2} c _{p_{2}}}{n _{1} c _{v_{1}} + n _{2} c _{v_{2}}} = \frac{n ( \frac{5}{2} R ) + 2 n ( \frac{7}{2} R )}{n ( \frac{3}{2} R ) + 2 n ( \frac{5}{2} R )} = \frac{5 + 14}{3 + 10} = \frac{19}{13}$

Q. There is a mixture of n moles of helium gas and 2n moles of oxygen gas. The value of CV​CP​​ for the mixture is

1523​

2740​

4567​

1319​