There is a current of 20 milliampere through an ideal choke coil of 1.5 H when connected to 220 volt, 50 hertz ac supply. The power consumed is :

Question

There is a current of 20 milliampere through an ideal choke coil of 1.5 H when connected to 220 volt, 50 hertz ac supply. The power consumed is : (A) Zero (B) 220×20×10-3 watt (C) 220×50 watt (D) 220×20×1.5 watt

Tardigrade Admin · Accepted Answer

Ideal choke is a wattless device. The phase angle between the current and emf is (π/2). This gives power factor cos φ = cos (π/2) = 0

Q. There is a current of 20 milliampere through an ideal choke coil of 1.5 H when connected to 220 volt, 50 hertz ac supply. The power consumed is :

Zero

$220 \times 20 \times 1 0^{- 3} w a tt$

$220 \times 50 w a tt$

$220 \times 20 \times 1.5 w a tt$

Ideal choke is a wattless device. The phase angle between the current and emf is $\frac{π}{2}$ . This gives power factor cos $ϕ = cos \frac{π}{2} = 0$

Q. There is a current of 20 milliampere through an ideal choke coil of 1.5 H when connected to 220 volt, 50 hertz ac supply. The power consumed is :

Zero

220×20×10−3watt

220×50watt

220×20×1.5watt

Ideal choke is a wattless device. The phase angle between the current and emf is 2π​. This gives power factor cos ϕ=cos2π​=0

$220 \times 20 \times 1 0^{- 3} w a tt$

$220 \times 50 w a tt$

$220 \times 20 \times 1.5 w a tt$

Ideal choke is a wattless device. The phase angle between the current and emf is $\frac{π}{2}$ . This gives power factor cos $ϕ = cos \frac{π}{2} = 0$