Q.
There exist positive integers A,B and C with no common factors greater than 1 , such that A log2005+Blog2002= C. The sum (A+B+C) equals
314
108
Continuity and Differentiability
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Solution:
AClog2005+Blog2002=C log200Alog5+log200Blog2=C Alog5+Blog2=Clog200=Clog(5223)=2Clog5+3Clog2 hence, A=2C B=3C
for no common factor greater than 1,C=1 ∴A=2;B=3⇒A+B+C=6