There are X number of aromatic positional isomers containing benzene ring with molecular formula C6H6O2 and Y number of tertiary aromatic amine containing benzene with molecular formula C8H11N. Report your answer as: X+Y=?

Question

There are X number of aromatic positional isomers containing benzene ring with molecular formula C6H6O2 and Y number of tertiary aromatic amine containing benzene with molecular formula C8H11N. Report your answer as: X+Y=? (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

These are aromatic positional isomer.So X=3 and Y=1 Solution

the number of tertiary aromatic amine is Y=1 Thus X+Y=4

Q. There are X number of aromatic positional isomers containing benzene ring with molecular formula C₆H₆O₂ and Y number of tertiary aromatic amine containing benzene with molecular formula C₈H₁₁N. Report your answer as : X+Y=?

These are aromatic positional isomer.So X=3 and Y=1

the number of tertiary aromatic amine is Y=1
Thus X+Y=4

Q. There are X number of aromatic positional isomers containing benzene ring with molecular formula C6H6O2 and Y number of tertiary aromatic amine containing benzene with molecular formula C8H11N. Report your answer as : X+Y=?

These are aromatic positional isomer.So X=3 and Y=1 the number of tertiary aromatic amine is Y=1 Thus X+Y=4

Q. There are X number of aromatic positional isomers containing benzene ring with molecular formula C₆H₆O₂ and Y number of tertiary aromatic amine containing benzene with molecular formula C₈H₁₁N. Report your answer as : X+Y=?

These are aromatic positional isomer.So X=3 and Y=1

the number of tertiary aromatic amine is Y=1
Thus X+Y=4