There are n bullets fired in 1 s by a gun. The mass of each of the bullets is m. If the speed of each of the bullets is v the average force of the recoil is

Question

There are n bullets fired in 1 s by a gun. The mass of each of the bullets is m. If the speed of each of the bullets is v the average force of the recoil is (A)  (mv/n)  (B)  (mv/ng)  (C)  (m2v2/n2)  (D) nmv

Tardigrade Admin · Accepted Answer

As, the change of momentum for a bullet is mv Average time for the firing of one bullet =(1/n) second Now, average force =(Δ p/Δ t) =(mv/1/n)=mnv

Q. There are n bullets fired in 1 s by a gun. The mass of each of the bullets is m. If the speed of each of the bullets is v the average force of the recoil is

$\frac{m v}{n}$

$\frac{m v}{n g}$

$\frac{m ^{2} v ^{2}}{n ^{2}}$

nmv

As, the change of momentum for a bullet is mv Average time for the firing of one bullet $= \frac{1}{n}$ second Now, average force $= \frac{Δ p}{Δ t}$ $= \frac{m v}{1/ n} = mn v$

Q. There are n bullets fired in 1 s by a gun. The mass of each of the bullets is m. If the speed of each of the bullets is v the average force of the recoil is

nmv​

ngmv​

n2m2v2​

nmv

As, the change of momentum for a bullet is mv Average time for the firing of one bullet =n1​ second Now, average force =ΔtΔp​ =1/nmv​=mnv

$\frac{m v}{n}$

$\frac{m v}{n g}$

$\frac{m ^{2} v ^{2}}{n ^{2}}$

As, the change of momentum for a bullet is mv Average time for the firing of one bullet $= \frac{1}{n}$ second Now, average force $= \frac{Δ p}{Δ t}$ $= \frac{m v}{1/ n} = mn v$