There are 4 defective items in a lot consisting of 10 items. From this lot we select 5 items at random. The probability that there will be 2 defective items among them is

Question

There are 4 defective items in a lot consisting of 10 items. From this lot we select 5 items at random. The probability that there will be 2 defective items among them is (A) (1/2) (B) (2/5) (C) (5/21) (D) (10/21)

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/mathematics/21c81e0f49f528a74b415e311b6bdb19-.png" /> p =( 4 C 2 ⋅ 6 C 3/ 10 C 5)=(10/21)

Q. There are 4 defective items in a lot consisting of 10 items. From this lot we select 5 items at random. The probability that there will be 2 defective items among them is

$\frac{1}{2}$

$\frac{2}{5}$

$\frac{5}{21}$

$\frac{10}{21}$

$p = \frac{^{4} C _{2} \cdot ^{6} C _{3}}{^{10} C _{5}} = \frac{10}{21}$

Q. There are 4 defective items in a lot consisting of 10 items. From this lot we select 5 items at random. The probability that there will be 2 defective items among them is

21​

52​

215​

2110​

p=10C5​4C2​⋅6C3​​=2110​

$\frac{1}{2}$

$\frac{2}{5}$

$\frac{5}{21}$

$\frac{10}{21}$

$p = \frac{^{4} C _{2} \cdot ^{6} C _{3}}{^{10} C _{5}} = \frac{10}{21}$