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  4. There are 4 defective items in a lot consisting of 10 items. From this lot we select 5 items at random. The probability that there will be 2 defective items among them is

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Q. There are 4 defective items in a lot consisting of 10 items. From this lot we select 5 items at random. The probability that there will be 2 defective items among them is

Probability - Part 2

Solution:

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$p =\frac{{ }^4 C _2 \cdot{ }^6 C _3}{{ }^{10} C _5}=\frac{10}{21}$