Tardigrade
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Tardigrade
Question
Mathematics
There are 3 straight lines, 4 circles and 5 parabolas in xy plane. Maximum number of their intersection point, is
Q. There are 3 straight lines, 4 circles and 5 parabolas in xy plane. Maximum number of their intersection point, is
1106
106
Permutations and Combinations
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A
129
B
149
C
169
D
189
Solution:
Line v/s line:
3
C
2
⋅
1
=
3
Circle v/s circle:
4
C
2
⋅
2
=
12
Parabola v/s Parabola:
5
C
2
⋅
4
=
40
Line v/s Circle:
3
C
1
⋅
4
C
1
⋅
2
=
24
Line v/s Parabola:
3
C
1
⋅
5
C
1
⋅
2
=
30
Circle v/s Parabola:
4
C
1
⋅
5
C
1
⋅
4
=
80
Total
=
189