There are 10 sound sources each producing intensity I at a point independently. They are incoherent. Average intensity of sound at that point will be:

Question

There are 10 sound sources each producing intensity I at a point independently. They are incoherent. Average intensity of sound at that point will be: (A) I (B) 10 I (C) 100 I (D) 0

Tardigrade Admin · Accepted Answer

Since the sources are incoherent there will be no sustained interference. Hence at the given point, Average intensity =I0=I1+I2+I3+⋅s +I10=10 I

Q. There are $10$ sound sources each producing intensity $I$ at a point independently. They are incoherent. Average intensity of sound at that point will be:

I

10 I

100 I

0

Since the sources are incoherent there will be no sustained interference.
Hence at the given point,
Average intensity $= I_{0} = I_{1} + I_{2} + I_{3} + \dots + I_{10} = 10 I$

Q. There are 10 sound sources each producing intensity I at a point independently. They are incoherent. Average intensity of sound at that point will be:

I

10 I

100 I

0

Since the sources are incoherent there will be no sustained interference. Hence at the given point, Average intensity =I0​=I1​+I2​+I3​+⋯+I10​=10I

Q. There are $10$ sound sources each producing intensity $I$ at a point independently. They are incoherent. Average intensity of sound at that point will be:

Since the sources are incoherent there will be no sustained interference.
Hence at the given point,
Average intensity $= I_{0} = I_{1} + I_{2} + I_{3} + \dots + I_{10} = 10 I$