The instantaneous speed is always positive as it is the magnitude of the velocity at an instant. So, it is positive during t=5s to t=10s.
For t=0s to t=5s, the motion is uniform and x−t graph has positive slope. So, the velocity and average velocity, instantaneous velocity and instantaneous speed are equal and positive.
During t=0s to t=5s, the slope of the graph is positive, hence the average velocity and the velocity both are positive.
During t=5s to t=10s, the slope of the graph is negative, hence the velocity is negative. Since, there is a change in sign of velocity at t=5s, so the car changes its direction at this instant.
Hence, option (a) is incorrect, while all other are correct.