The x and y coordinates of the particle at any time are x = 5t - 2t2 and y = 10t respectively, where x and y are in meters and t in seconds. The acceleration of the particle at t = 2s is :

Question

The x and y coordinates of the particle at any time are x = 5t - 2t2 and y = 10t respectively, where x and y are in meters and t in seconds. The acceleration of the particle at t = 2s is : (A) 5 m/s2 (B) -4 ms2 (C)  -8 ms2 (D) 0

Tardigrade Admin · Accepted Answer

x=5 t-2 t2 y=10 t (d x/d t)=5-4 t (d y/d t)=10 vx=5-4 t vy=10 (d v/d t) x=-4 (d v/d t) y=10 ax=-4 ay=0 Acceleration of particle at t=2 s is =-4 m / s 2

Q. The x and y coordinates of the particle at any time are $x = 5 t - 2 t^{2}$ and $y = 10 t$ respectively, where $x$ and $y$ are in meters and t in seconds. The acceleration of the particle at $t = 2 s$ is :

$5 m / s^{2}$

$- 4 m s^{2}$

$- 8 m s^{2}$

0

$x = 5 t - 2 t^{2} y = 10 t$
$\frac{d x}{d t} = 5 - 4 t \frac{d y}{d t} = 10$
$v_{x} = 5 - 4 t v_{y} = 10$
$\frac{d v}{d t} x = - 4 \frac{d v}{d t} y = 10$
$a_{x} = - 4 a_{y} = 0$
Acceleration of particle at $t = 2 s$ is $= - 4 m / s^{2}$

Q. The x and y coordinates of the particle at any time are x=5t−2t2 and y=10t respectively, where x and y are in meters and t in seconds. The acceleration of the particle at t=2s is :

5m/s2

−4ms2

−8ms2

0

x=5t−2t2y=10t dtdx​=5−4tdtdy​=10 vx​=5−4tvy​=10 dtdv​x=−4dtdv​y=10 ax​=−4ay​=0 Acceleration of particle at t=2s is =−4m/s2

Q. The x and y coordinates of the particle at any time are $x = 5 t - 2 t^{2}$ and $y = 10 t$ respectively, where $x$ and $y$ are in meters and t in seconds. The acceleration of the particle at $t = 2 s$ is :

$5 m / s^{2}$

$- 4 m s^{2}$

$- 8 m s^{2}$

$x = 5 t - 2 t^{2} y = 10 t$
$\frac{d x}{d t} = 5 - 4 t \frac{d y}{d t} = 10$
$v_{x} = 5 - 4 t v_{y} = 10$
$\frac{d v}{d t} x = - 4 \frac{d v}{d t} y = 10$
$a_{x} = - 4 a_{y} = 0$
Acceleration of particle at $t = 2 s$ is $= - 4 m / s^{2}$