The work done in pulling up a block of wood weighing 200N for length of 10 m on a smooth plane inclined at an angle of 30° with the horizontal is

Question

The work done in pulling up a block of wood weighing 200N for length of 10 m on a smooth plane inclined at an angle of 30° with the horizontal is (A) 18 KJ (B) 20 KJ (C) 10 KJ (D) None

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/f39eca48e53ba0f714daf519244261dd-.png" /> w=mg sin θ × s =m g sin 30° × s w =200 × 10 × (1/2) × 10 w =104 J=10 kJ

Q. The work done in pulling up a block of wood weighing $200 N$ for length of $10 m$ on a smooth plane inclined at an angle of $3 0^{\circ}$ with the horizontal is

$18 K J$

$20 K J$

$10 K J$

None

$w = m g sin θ \times s = m g sin 3 0^{\circ} \times s$
$w = 200 \times 10 \times \frac{1}{2} \times 10$
$w = 1 0^{4} J = 10 k J$

Q. The work done in pulling up a block of wood weighing 200N for length of 10m on a smooth plane inclined at an angle of 30∘ with the horizontal is

18KJ

20KJ

10KJ