The work done in pulling up a block of wood weighing 2 kN for a length of 10 m on a smooth plane inclined at an angle of 15o with the horizontal is:

Question

The work done in pulling up a block of wood weighing 2 kN for a length of 10 m on a smooth plane inclined at an angle of 15o with the horizontal is: (A)  9.82 kJ  (B)  89 kJ  (C)  4.35 kJ  (D)  5.17 kJ

Tardigrade Admin · Accepted Answer

Here: weight of block w=2 kN, Distance d=10 m Angle of inclination on the plane α=15° The block will be pulled up on a smooth plane Hence, force of resistance due to inclination F =w sin α=2 × 103 sin 15° =2 × 103 × 0.2588 =0.5176 kN Now work done, W =F d=0.5176 × 103 × 10 =5: 17 kN

Q. The work done in pulling up a block of wood weighing $2 k N$ for a length of $10 m$ on a smooth plane inclined at an angle of $15^{o}$ with the horizontal is:

$9.82 k J$

$89 k J$

$4.35 k J$

$5.17 k J$

Q. The work done in pulling up a block of wood weighing 2kN for a length of 10m on a smooth plane inclined at an angle of 15o with the horizontal is:

9.82kJ

89kJ

4.35kJ

5.17kJ

Here : weight of block w=2kN, Distance d=10m Angle of inclination on the plane α=15∘ The block will be pulled up on a smooth plane Hence, force of resistance due to inclination F=wsinα=2×103sin15∘ =2×103×0.2588 =0.5176kN Now work done, W=Fd=0.5176×103×10 =5:17kN

Q. The work done in pulling up a block of wood weighing $2 k N$ for a length of $10 m$ on a smooth plane inclined at an angle of $15^{o}$ with the horizontal is:

$9.82 k J$

$89 k J$

$4.35 k J$

$5.17 k J$