The work done in moving a point charge of 10μ C through a distance of 3 cm along the equatorial axis of an electric dipole is

Question

The work done in moving a point charge of 10μ C through a distance of 3 cm along the equatorial axis of an electric dipole is (A) 10 × 10-6 J (B) 30 × 10-6 J (C) 20 × 10-6 J (D) 5 × 10-6 J

Tardigrade Admin · Accepted Answer

Electrostatic potential is zero along the equatorial line of the dipole

Q. The work done in moving a point charge of $10 μ C$ through a distance of $3 c m$ along the equatorial axis of an electric dipole is

$10 \times 1 0^{- 6} J$

$30 \times 1 0^{- 6} J$

$20 \times 1 0^{- 6} J$

$5 \times 1 0^{- 6} J$

zero

Electrostatic potential is zero along the equatorial line of the dipole

Q. The work done in moving a point charge of 10μC through a distance of 3cm along the equatorial axis of an electric dipole is

10×10−6J

30×10−6J

20×10−6J

5×10−6J

zero

Electrostatic potential is zero along the equatorial line of the dipole

Q. The work done in moving a point charge of $10 μ C$ through a distance of $3 c m$ along the equatorial axis of an electric dipole is

$10 \times 1 0^{- 6} J$

$30 \times 1 0^{- 6} J$

$20 \times 1 0^{- 6} J$

$5 \times 1 0^{- 6} J$