The work done in ergs for the reversible expansion of 1 mole of an ideal gas from a volume of 10 litres to 20 litres at 25°C is

Question

The work done in ergs for the reversible expansion of 1 mole of an ideal gas from a volume of 10 litres to 20 litres at 25°C is (A) -2.303 × 298 × 0.082 log 2 (B) -298 × 107 × 8.31 × 2.3031 log 2 (C) -2.303 × 298 × 0.082 log 0.5 (D) -8.31 × 107 × 298 × 2.303 log 0.5

Tardigrade Admin · Accepted Answer

W = -2.303 n RT(V2/V1) = -2.303 × 1 × 8.314 × 107 × 298 log (20/10) = -298 × 107 × 8.314 × 2.303 log 2

Q. The work done in ergs for the reversible expansion of 1 mole of an ideal gas from a volume of 10 litres to 20 litres at $2 5^{\circ} C$ is

$- 2.303 \times 298 \times 0.082 l o g 2$

$- 298 \times 107 \times 8.31 \times 2.3031 l o g 2$

$- 2.303 \times 298 \times 0.082 l o g 0.5$

$- 8.31 \times 107 \times 298 \times 2.303 l o g 0.5$

$W = - 2.303 n RT \frac{V _{2}}{V _{1}}$
$= - 2.303 \times 1 \times 8.314 \times 107 \times 298 l o g \frac{20}{10}$
$= - 298 \times 1 0^{7} \times 8.314 \times 2.303 l o g 2$

Q. The work done in ergs for the reversible expansion of 1 mole of an ideal gas from a volume of 10 litres to 20 litres at 25∘C is

−2.303×298×0.082log2

−298×107×8.31×2.3031log2

−2.303×298×0.082log0.5

−8.31×107×298×2.303log0.5