The work done in dragging a stone of mass 100 kg up an inclined plane 1 in 100 through a distance of 10 m is (take g = 9.8 m/s2)

Question

The work done in dragging a stone of mass 100 kg up an inclined plane 1 in 100 through a distance of 10 m is (take g = 9.8 m/s2) (A) zero (B) 980 J (C) 9800 J (D) 98 J

Tardigrade Admin · Accepted Answer

Slope of inclined plane, sin θ = 1/100 Component of weight down the inclined plane F = mg = sin θ = 100 × 9.8 × (1/100) = 9.8 N s = distance moved = 10 m W = Fs = 9.8 × 10 = 98 J

Q. The work done in dragging a stone of mass $100 k g$ up an inclined plane 1 in $100$ through a distance of $10 m$ is (take $g = 9.8 m / s^{2}$ )

zero

980 J

9800 J

98 J

Slope of inclined plane, sin $θ = 1/100$

Component of weight down the inclined plane

$F = m g = sin θ = 100 \times 9.8 \times \frac{1}{100}$

$= 9.8 N$

$s =$ distance moved $= 10 m$

$W = F s = 9.8 \times 10 = 98 J$

Q. The work done in dragging a stone of mass 100kg up an inclined plane 1 in 100 through a distance of 10m is (take g=9.8m/s2)