The work done in bringing a unit positive charge from infinite distance to a point at distance x from a positive charge Q is W. Then the potential φ at that point is

Question

The work done in bringing a unit positive charge from infinite distance to a point at distance x from a positive charge Q is W. Then the potential φ at that point is (A) (WQ/x) (B) W (C) (W/x) (D) WQ

Tardigrade Admin · Accepted Answer

Electric potential at a point in an electric field is defined as the work done in bringing a unit positive charge from infinity to that point.
Or,

V = \frac{W}{q}

Since charge is of magnitude unity, Hence electric potential at that point will be equal to the work done

∴ ϕ = W

Q. The work done in bringing a unit positive charge from infinite distance to a point at distance $x$ from a positive charge $Q$ is $W$ . Then the potential $ϕ$ at that point is

$\frac{W Q}{x}$

$W$

$\frac{W}{x}$

$W Q$

Electric potential at a point in an electric field is defined as the work done in bringing a unit positive charge from infinity to that point.
Or, $V = \frac{W}{q}$
Since charge is of magnitude unity, Hence electric potential at that point will be equal to the work done
$∴ ϕ = W$

Q. The work done in bringing a unit positive charge from infinite distance to a point at distance x from a positive charge Q is W. Then the potential ϕ at that point is

xWQ​

W

xW​

WQ

Electric potential at a point in an electric field is defined as the work done in bringing a unit positive charge from infinity to that point. Or, V=qW​ Since charge is of magnitude unity, Hence electric potential at that point will be equal to the work done ∴ϕ=W

Q. The work done in bringing a unit positive charge from infinite distance to a point at distance $x$ from a positive charge $Q$ is $W$ . Then the potential $ϕ$ at that point is

$\frac{W Q}{x}$

$W$

$\frac{W}{x}$

$W Q$

Electric potential at a point in an electric field is defined as the work done in bringing a unit positive charge from infinity to that point.
Or, $V = \frac{W}{q}$
Since charge is of magnitude unity, Hence electric potential at that point will be equal to the work done
$∴ ϕ = W$