The work done in an open vessel at 300 K, when 112 g iron reacts with dil HCl to give FeCl2, is nearly

Question

The work done in an open vessel at 300 K, when 112 g iron reacts with dil HCl to give FeCl2, is nearly (A) 1.1 kcal (B) 0.6 kcal (C) 0.3 kcal (D) 0.2 kcal

Tardigrade Admin · Accepted Answer

2Fe (s) + 4HCl → 2FeCl2 + 2H2 ∴ Δng = 2 mol We know, w = - pΔV = - ΔngRT = - 2 mol × 2 cal mol-1 K-1 × 300 K = - 1.2 kcal So, work done = 1.2 kcal

Q. The work done in an open vessel at $300 K$ , when $112 g$ iron reacts with dil $H Cl$ to give $F e C l_{2}$ , is nearly

1.1 kcal

0.6 kcal

0.3 kcal

0.2 kcal

$2 F e (s) + 4 H Cl \to 2 F e C l_{2} + 2 H_{2}$
$∴ Δ n_{g} = 2 m o l$
We know,
$w = - p Δ V = - Δ n_{g} RT$
$= - 2 m o l \times 2 c a l m o l^{- 1} K^{- 1} \times 300 K$
$= - 1.2 k c a l$
So, work done $= 1.2 k c a l$

Q. The work done in an open vessel at 300K, when 112g iron reacts with dil HCl to give FeCl2​, is nearly