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  4. The work done in an open vessel at 300 K, when 112 g iron reacts with dil HCl to give FeCl2, is nearly

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Q. The work done in an open vessel at $300\, K$, when $112\, g$ iron reacts with dil $HCl$ to give $FeCl_2$, is nearly

Thermodynamics

Solution:

$2Fe (s) + 4HCl \to 2FeCl_2 + 2H_2$
$∴ Δn_g = 2\, mol$
We know,
$w = - pΔV = - Δn_gRT$
$= - 2\, mol × 2 \,cal\, mol^{-1} K^{-1} × 300\, K$
$= - 1.2\, kcal$
So, work done $= 1.2 \,kcal$