The work done during the free expansion of one mole of an ideal gas at 27°C to twice its original volume is (given: RT=2494 J mol-1, In 2 = 0.7, log 2 = 0.3)

Question

The work done during the free expansion of one mole of an ideal gas at 27°C to twice its original volume is (given: RT=2494 J mol-1, In 2 = 0.7, log 2 = 0.3) (A) 1746 J mol-1 (B) -1746 J mol-1 (C) zero (D) 748.2 J mol-1

Tardigrade Admin · Accepted Answer

The work done during reversible process is given by ∫ Pdv Since, here no work is done against external pressure (as expansion is free), the work done is zero

Q. The work done during the free expansion of one mole of an ideal gas at $2 7^{\circ} C$ to twice its original volume is (given : $RT = 2494 J m o l^{- 1}$ , In $2 = 0.7, l o g 2 = 0.3)$

$1746 J m o l^{- 1}$

$- 1746 J m o l^{- 1}$

$zero$

$748.2 J m o l^{- 1}$

The work done during reversible process is given by $\int P d v$ Since, here no work is done against external pressure (as expansion is free), the work done is zero

Q. The work done during the free expansion of one mole of an ideal gas at 27∘C to twice its original volume is (given : RT=2494Jmol−1, In 2=0.7,log2=0.3)

1746Jmol−1

−1746Jmol−1

zero

748.2Jmol−1