The work done during combustion of 9 × 10-2 Kg of ethane, C2H6 (g) at 300 K is (Given R = 8.314 J deg-1 mol-1 , atomic mas C = 12 , H = 1)

Question

The work done during combustion of 9 × 10-2 Kg of ethane, C2H6 (g) at 300 K is (Given R = 8.314 J deg-1 mol-1 , atomic mas C = 12 , H = 1) (A) 6.236 kJ (B) -6.236 kJ (C) 18.71 kJ (D) - 18.71 kJ

Tardigrade Admin · Accepted Answer

Work done in a chemical reaction, W =Δ n g RT where, Δ n g = number of moles of gaseous products - number of moles of gaseous reactants. Combustion of ethane is- C 2 H 6( g )+(7/2) O 2( g ) arrow 2 CO 2( g )+3 H 2 O ( l ) ∴ n g =2-4.5=-2.5 W =(2.5 mol )(8.314 JK -1 mol -1) × 300 K =6235.5 kJ =6.2355 J Now , 1 mole of C 2 H 6=30 gm of C 2 H 6=6.2355 kJ Work done for combustion of 30 gm of C 2 H 6=6.2355 kJ ∴ Work done for combustion of 90 gm of C 2 H 6 =(6.2355 × 90/30) =18.7065 kJ =18.71 kJ

Q. The work done during combustion of $9 \times 1 0^{- 2} K g$ of ethane, $C_{2} H_{6} (g)$ at $300 K$ is
(Given $R = 8.314 J d e g^{- 1} m o l^{- 1}$ , atomic mas $C = 12, H = 1$ )

$6.236 k J$

$- 6.236 k J$

$18.71 k J$

$- 18.71 k J$

Q. The work done during combustion of 9×10−2Kg of ethane, C2​H6​(g) at 300K is (Given R=8.314Jdeg−1mol−1 , atomic mas C=12,H=1)

6.236kJ

−6.236kJ

18.71kJ

−18.71kJ

Q. The work done during combustion of $9 \times 1 0^{- 2} K g$ of ethane, $C_{2} H_{6} (g)$ at $300 K$ is
(Given $R = 8.314 J d e g^{- 1} m o l^{- 1}$ , atomic mas $C = 12, H = 1$ )

$6.236 k J$

$- 6.236 k J$

$18.71 k J$

$- 18.71 k J$